{"id":17849,"date":"2024-03-12T14:55:59","date_gmt":"2024-03-12T14:55:59","guid":{"rendered":"https:\/\/soicau3062.minhngocxoso.com\/cach-bat-tong-dac-biet-bach-phat-bach-trung\/"},"modified":"2024-03-12T14:55:59","modified_gmt":"2024-03-12T14:55:59","slug":"cach-bat-tong-dac-biet-bach-phat-bach-trung","status":"publish","type":"post","link":"https:\/\/soicauxosomienphi.com\/cach-bat-tong-dac-biet-bach-phat-bach-trung\/","title":{"rendered":"C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t b\u00e1ch ph\u00e1t b\u00e1ch tr\u00fang"},"content":{"rendered":"
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/strong> l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u ph\u1ed5 bi\u1ebfn, mang l\u1ea1i hi\u1ec7u qu\u1ea3 cao cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. <\/p>\n Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y kh\u00e1 \u0111\u01a1n gi\u1ea3n v\u00e0 \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u00e3 \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi ki\u1ec3m ch\u1ee9ng. C\u1ee5 th\u1ec3, b\u1ea1n s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c sau: V\u00ed d\u1ee5:<\/p>\n B\u01b0\u1edbc 1:<\/strong> L\u1ea5y k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc ng\u00e0y 29\/7\/2024 \u0111\u1ec3 t\u1ea1o \u0111\u1ebf c\u1ee7a tam gi\u00e1c Pascal<\/p>\n <\/p>\n B\u01b0\u1edbc 2<\/strong>: L\u1eadp tam gi\u00e1c Pascal<\/p>\n <\/p>\n B\u01b0\u1edbc 3:<\/strong> L\u1ea5y 2 s\u1ed1 \u1edf \u0111\u1ec9nh tam gi\u00e1c (32) \u0111\u1ec3 \u0111\u00e1nh l\u00f4 h\u00f4m sau<\/p>\n =>> K\u1ebft qu\u1ea3 l\u00f4 32 v\u1ec1 ng\u00e0y 30\/7:<\/p>\n <\/p>\n \u0110\u1ed1i v\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, b\u1ea1n ch\u1ec9 c\u1ea7n th\u1ef1c hi\u1ec7n c\u00e1c b\u01b0\u1edbc \u0111\u01a1n gi\u1ea3n nh\u01b0 sau. => C\u00f3 5 tr\u01b0\u1eddng h\u1ee3p c\u00f3 th\u1ec3 x\u1ea3y ra: L\u01b0u \u00fd: C\u00e1ch \u0111\u00e1nh n\u00e0y \u0111\u01a1n gi\u1ea3n l\u00e0 ch\u1ec9 d\u1ef1a v\u00e0o t\u1ed5ng \u0111\u1ec1 ng\u00e0y \u0111\u1ea7u ti\u00ean trong tu\u1ea7n (th\u1ee9 2). C\u1ee5 th\u1ec3, b\u1ea1n l\u1ea5y 2 con s\u1ed1 cu\u1ed1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00f4m th\u1ee9 2 c\u1ed9ng l\u1ea1i, l\u1ea5y s\u1ed1 t\u1ed5ng \u0111\u1ec3 l\u1eadp d\u00e0n \u0111\u1ec1 c\u00f3 t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n V\u00ed d\u1ee5:<\/strong> th\u1ee9 2 ng\u00e0y 16\/9\/2024 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ra 03797<\/strong>=> T\u1ed5ng 6 K\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 c\u00e1c ng\u00e0y sau \u0111\u00f3 ra sao?<\/em> \u0110\u1ebfn ng\u00e0y 21\/9 th\u00ec c\u1ea7u d\u1eebng.<\/p>\n \u0110\u00e2y c\u0169ng l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p r\u1ea5t hay t\u1eeb kinh nghi\u1ec7m ch\u01a1i l\u00f4 tr\u01b0\u1eddng k\u1ef3 c\u1ee7a c\u00e1c cao th\u1ee7. Khi t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t r\u01a1i v\u00e0o nh\u1eefng tr\u01b0\u1eddng h\u1ee3p d\u01b0\u1edbi \u0111\u00e2y th\u00ec b\u1ea1n c\u00f3 th\u1ec3 c\u00e2n nh\u1eafc \u0111\u00e1nh \u0111\u1ec1 c\u00e1c d\u00e0n t\u1ed5ng sau:<\/p>\n V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, b\u1ea1n ch\u1ec9 c\u1ea7n c\u1ed9ng c\u1ea3 d\u00e3y x\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u1ea1i, l\u1ea5y t\u1ed5ng \u0111\u00f3 l\u00e0m c\u1eb7p l\u00f4 \u0111\u00e1nh ng\u00e0y h\u00f4m sau. X\u00e1c su\u1ea5t tr\u00fang \u1edf m\u1ee9c t\u01b0\u01a1ng \u0111\u1ed1i, tuy nhi\u00ean n\u1ebfu k\u1ebft h\u1ee3p ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f9ng nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c \u0111\u1ec3 soi c\u1ea7u th\u00ec \u0111\u1ed9 ch\u00ednh x\u00e1c s\u1ebd t\u0103ng l\u00ean r\u1ea5t cao.<\/p>\n Nh\u01b0 v\u1eady l\u00e0 b\u1ea1n v\u1eeba c\u00f3 th\u00eam 5 c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 h\u1eefu \u00edch \u0111\u1ec3 lu\u1eadn gi\u1ea3i l\u00f4 \u0111\u1ec1. Nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u0169ng \u0111ang \u0111\u01b0\u1ee3c \u0111\u1ec3 ch\u1ed1t s\u1ed1 h\u00e0ng ng\u00e0y. N\u1ebfu b\u1ea1n \u0111\u00e3 hi\u1ec3u h\u01a1n v\u1ec1 ngu\u1ed3n g\u1ed1c v\u00e0 c\u01a1 s\u1edf c\u1ee7a c\u00e1c con l\u00f4 m\u00e0 ch\u00fang t\u00f4i d\u1ef1 \u0111o\u00e1n, h\u00e3y c\u00f9ng ch\u00fang t\u00f4i v\u1ec1 b\u1edd an to\u00e0n!<\/p>\n
\nV\u1ec1 c\u01a1 b\u1ea3n, c\u00e1ch b\u1eaft l\u00f4 \u0111\u1ec1 t\u1ed5ng \u0111\u1eb7c bi\u1ec7t kh\u00f4ng kh\u00f3. N\u00f3 ch\u1ec9 \u0111\u00f2i h\u1ecfi ng\u01b0\u1eddi ch\u01a1i c\u00f3 t\u00ednh ki\u00ean tr\u00ec v\u00e0 th\u1eddi gian \u0111\u1ec3 c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng \u0111\u00fang ph\u01b0\u01a1ng ph\u00e1p.<\/p>\nC\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo tam gi\u00e1c Pascal<\/strong><\/h3>\n
\nL\u1ea5y d\u00e3y s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u1ea5t ng\u00e0y h\u00f4m tr\u01b0\u1edbc gh\u00e9p l\u1ea1i th\u00e0nh 1 d\u00e3y 10 s\u1ed1. C\u1ed9ng 2 s\u1ed1 li\u1ec1n k\u1ec1 nhau \u0111\u1ec3 cho ra k\u1ebft qu\u1ea3, t\u1ea1o th\u00e0nh d\u00e3y s\u1ed1 k\u1ebf ti\u1ebfp. N\u1ebfu b\u1ed1 tr\u00ed theo h\u00ecnh tam gi\u00e1c c\u00f3 \u0111\u1ec9nh h\u01b0\u1edbng l\u00ean th\u00ec k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng s\u1ebd l\u00e0 con l\u00f4 \u0111\u1ec3 b\u1ea1n \u0111\u00e1nh v\u00e0o ng\u00e0y h\u00f4m sau.<\/p>\nC\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t 2 ng\u00e0y<\/strong><\/h3>\n
\nCoi \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, \u0111\u1ec1 ng\u00e0y th\u1ee9 2 l\u00e0 CD, ta c\u00f3 c\u00f4ng th\u1ee9c:<\/p>\n\n
\nTr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu E < 10, F < 10 l\u1ea5y 10 \u2013 E = X, 10 \u2013 F = Y. Nh\u01b0 v\u1eady XY l\u00e0 con l\u00f4 \u0111\u1ec3 \u0111\u00e1nh ng\u00e0y th\u1ee9 3
\nTr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu E > 10, F < 10 L\u1ea5y 20 \u2013 E = X, 10 \u2013 F = Y. Ng\u00e0y th\u1ee9 3 \u0111\u00e1nh l\u00f4 XY v\u1eeba t\u00ednh \u0111\u01b0\u1ee3c
\nTr\u01b0\u1eddng h\u1ee3p 3: N\u1ebfu E > 10, F > 10 L\u1ea5y 20 \u2013 E = X, 20 \u2013 F = Y. L\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 XY
\nTr\u01b0\u1eddng h\u1ee3p 4: N\u1ebfu E < 10, F > 10. L\u1ea5y hi\u1ec7u 10 \u2013 E = X, 20 \u2013 F = Y. Ng\u00e0y th\u1ee9 3 \u0111\u00e1nh l\u00f4 YX
\nTr\u01b0\u1eddng h\u1ee3p 5: E = 0 ho\u1eb7c 10, F = 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0<\/p>\n
\nC\u1ea7u n\u00e0y c\u00f3 th\u1ec3 \u0111\u1eb7t c\u01b0\u1ee3c li\u00ean ti\u1ebfp trong 3 \u2013 4 ng\u00e0y.
\nN\u1ebfu h\u00f4m sau c\u1ea7u kh\u00f4ng ra th\u00ec t\u1ea1m ngh\u1ec9 1 ng\u00e0y.
\nN\u1ebfu c\u1ea7u ra \u0111\u00fang ng\u00e0y ngh\u1ec9 th\u00ec b\u1ecf c\u1ea7u.
\nN\u1ebfu c\u1ea7u n\u1ed5 l\u1ed9n th\u00ec ngh\u1ec9 n\u1eeda tu\u1ea7n ch\u01a1i l\u1ea1i c\u1ea7u n\u00e0y.
\nN\u1ebfu trong v\u00f2ng 6 ng\u00e0y c\u1ea7u n\u00e0y kh\u00f4ng n\u1ed5 th\u00ec ch\u1eafc ch\u1eafn s\u1ebd n\u1ed5 ng\u00e0y th\u1ee9 7. ch\u01a1i ti\u1ebfp 3 ng\u00e0y.<\/p>\nC\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 2 \u0111\u1ea7u tu\u1ea7n<\/strong><\/h3>\n
\nV\u1edbi t\u1ed5ng \u0111\u1ec1 6, ch\u00fang ta c\u00f3 d\u00e0n t\u1ed5ng 6 nh\u01b0 sau: 606, 88, 979, 515, 424, 33<\/strong><\/p>\n
\nTh\u1eadt b\u1ea5t ng\u1edd khi m\u00e0 t\u1ed5ng 6 ra li\u00ean ti\u1ebfp 5 ng\u00e0y!<\/em><\/p>\n\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo <\/strong>l\u00f4 \u0111\u1ec1 <\/strong>b\u1ea1c nh\u1edb<\/strong><\/h3>\n
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C\u00e1ch b\u1eaft l\u00f4 \u0111\u1ec1 t\u1eeb t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1<\/strong><\/h3>\n